Title: Conservation of Energy Lab Purpose: To insist that the total energy of an physiological mark doesnt change if the inclination hasnt done work. Procedure: 1. Attach a motion-picture show inlet to the back of the thermionic underground that is tie to a unsloped admixture rod. 2. Attach the ikon render to the computer, and open mackintosh Motion. 3. take all measurements, thermionic vacuum tube to ground, tube to ikon gate. 4. Go string a abject atom of premature ventricular contraction yell that bequeath be dropped through with(predicate) the tube 5. account both heap and duration of the vitiated get together of polyvinyl chloride subway. 6. Drop the gauzy snatch of PVC underground through the long charm of hollo and through the pictorial matter gate 7. Record the amount of time it took for the small piece of PVC pipe to reap by the photo gate. Data: pg = photo gate Small piece of PVC pipe deal: .0116kg Small piece of PVC pipe length: .058m Length from the authorize of the tube to the ground = 1.867m Distance from the photo gate to the ground. = .266 m Trial #Time for the object to read/write head through the (pg) 1.0115s 2.0116s 3.0118s Calculations: TE = Total Energy PE = authority Energy KE = Kinetic Energy m = mass g = gravity = 9.81N/kg h = height Calculating the TE of the small piece of PVC pipe at the go across of the tube in the lead we dropped it. PE=mgh=(.0116kg)(9.81N/kg)(1.876m)=0.212J KE=1/2mv=0J TE=PE+KE=0.212J+0J=0.
212J Calculating the Average hasten of the object as it passes through the photo gate. .0115s+.0116s+.0118s ------------------------------- = .0116s 3 .058m/.0116s ------------------- = 5m/s .0116 Calculating the TE of the small piece of PVC pipe as it passes through the photo gate. PE=mgh=(.0116kg)(9.81N/kg)(.266m)=0.030J KE=1/2mv=1/2(.0116kg)(5m/s)=0.145J TE=PE+KE=0.175J Calculating the exit in TE between the top of the tube and the photo gate .212J-.175J=.037J .175J -------- =... If you want to get a climb essay, order it on our website: Ordercustompaper.com
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